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    • CommentAuthorGavin_A
    • CommentTimeSep 26th 2012
     
    I don't turn the shower up because it's not steamy enough.

    I don't boil the kettle for longer because it's not steamy enough*.

    I don't add more water to my clothes to dry them for longer because they're not steamy enough.

    Therefore there is no additional energy used to increase the RH level in the house via these means.

    As for eating more... humans don't regulate their food intake to the degree that a 0.1% increase in their daily energy use results in a 0.1% increase in food consumption. They just get very marginally fatter or thinner.

    "Think about it. In equilibrium, as much water vapour condenses out onto surfaces as evaporates from them. If you make conditions drier than the equilibrium, more water evaporates than condenses and there is a net energy of vaporisation that has to come from somewhere!"

    how exactly would more water be evaporating than condenses onto the surfaces? Where does it come from if it hadn't previously condensed on that surface?

    Unless you're talking about an extremely vapour impermeable building, much of the vapour that condenses will also migrate through the wall / ceiling anyway, not just continuously condense and evaporate within the building envelope.

    There obviously is a net energy of vapourisation that has to come from somewhere, but this isn't new energy, it's energy that was already being spent in the form of showers, drying clothes etc. The choice here is whether to throw the much of this energy away during ventilation as in the case with an MHRV system, or recycle a much greater proportion of it via an EAHP.
  1.  
    Malcolm

    I've just realised the air flow you use in your calculation is the air moved in 1.7 hours of operation, not 1 hour as is typically used.

    With the reduced air change rate the Ecocent now delivers a net heat gain of 100W for a power consumed of 810W. The numbers for the MVHR & external ASHP combination haven't changed, with a net heat gain of 2048W for a power consumed of 870W. The amended spreadsheet is attached.

    Note that this spreadsheet doesn't make any assumption about the exhaust heat pump exhaust air temperature. It relies purely on the Ecocent data you have provided & typical MVHR figures.

    The heat pump doesn't accumulate energy; it consumes energy in moving energy from one place to another.

    Time is not relevant because all the calculations are in power.

    I have forwarded the amended spreadsheet to Gavin_A, so that he can add the moisture aspects.

    David
    • CommentAuthorqeipl
    • CommentTimeSep 27th 2012 edited
     
    David,

    As far as I understand your calculations are wrong for all the reasons that I gave in my last post.
    I'm not going to convince you of this and if you stick to your current tack you're not going to convince me that your understanding of the energy flows is correct.
    Maybe Gavin will be able to put one or both of us right.

    Malcolm
  2.  
    Posted By: qeiplAs far as I understand your calculations are wrong for all the reasons that I gave in my last post.
    I dealt with those in my reply, but lets take them one at a time.
    Posted By: qeiplOn the green side: You are assuming an exhaust air temperature for the heat pump with no evidence to support the assumption.
    No I'm not. The only exhaust heat pump data I've used is the air flow, input power & output power provided by your good self. No other energy is recovered from the extracted air than that delivered by the exhaust heat pump, so we only need to concern oursleves with the power available at the heat pump output.
    Posted By: qeiplYou then use this assumption to determine the VHL by erroneous means. What you call 'Ventilation Heat Loss' is the energy available to the heat pump from the air, which is the enthalpy of air at 21C at whatever RH, not the enthalpy of the differential temperature (in v. out).
    No I don't. The Ventilation Heat Loss is caused by the air drawn into the house by the exhaust heat pump. It does not depend on the heat pump performance, only its air flow rate.
    Posted By: qeiplThe net heat gain is the VHL minus the power recovered: you have it the wrong way round.
    No it isn't. You don't gain heat by removing warm air & replacing it with cold air.
    Posted By: qeiplOn the blue side: For a valid comparison you have to run the MVHR for 3.5 hours so that it has provided the same number of air changes as the heat pump, which means the VHL must be the same as the green side.
    Time isn't relevant if you use power, i.e. the energy which is consumed, gained or lost in one second. The MVHR can run for 24 hours & the power numbers will not change unless the temperatures change. The MVHR doesn't need to recover the same total amount of energy as the exhaust heat pump because the external ASHP is there to pump energy into the house. The ventilation heat loss will always be greater with the exhuast heat pump because it requires enough air flow to provide the energy for the heat pump; the external ASHP can take unlimited amounts of energy from outside without affecting the ventilation heat loss.
    Posted By: qeiplIn terms of enthalpy the MVHR cannot be 90% efficient. The laws of physics don't allow it.
    I have calculated the Power Available to Heat Exchanger by only considering the sensible heat & the 90% efficiency is defined in the same way, so I don't believe the efficiency is over-stated. Put it another way, if moisture is taken into consideration then the Power Available to Heat Exchanger will increase & the efficiency will reduce, but the Recovered Power will be at least the same.
    Posted By: qeiplIn general: You don't give a value for the RH of the air, which is required so that we know the energy content of the air.
    This is not required as I have referred only to sensible heat. Although you have referenced it in your table, the only mechanism for recovering latent heat is in the heat pump. Do your COP figures for the Ecocent include energy recovered from latent heat? If so, what relative humidity was assumed for these?
    Posted By: qeiplIgnoring time means that the cumulative energy gain from the exhaust heat pump isn't accounted for.
    There is no cumulative energy gain from the exhaust heat pump, other than that you would obtain by running a fixed output power heater for a longer period. In other words, you can assess the net energy gain over a given time period by simply multiplying the time period in seconds by the net power gain.

    David
    • CommentAuthorbatkinson
    • CommentTimeSep 27th 2012
     
    Im intersted to know how they get round Building Regs as you just can not replace them with a more inefficient system
    • CommentAuthorGavin_A
    • CommentTimeSep 27th 2012
     
    Posted By: qeiplDavid,

    As far as I understand your calculations are wrong for all the reasons that I gave in my last post.
    I'm not going to convince you of this and if you stick to your current tack you're not going to convince me that your understanding of the energy flows is correct.
    Maybe Gavin will be able to put one or both of us right.

    Malcolm

    I shall attempt to.

    I was working on it last night, but kept ending up with figures that seemed to be a factor of 10 out, but couldn't work out why. I'll attempt to rework the figures when my brain is a bit fresher.
    • CommentAuthordjh
    • CommentTimeSep 27th 2012
     
    Posted By: Gavin_A
    "Think about it. In equilibrium, as much water vapour condenses out onto surfaces as evaporates from them. If you make conditions drier than the equilibrium, more water evaporates than condenses and there is a net energy of vaporisation that has to come from somewhere!"

    how exactly would more water be evaporating than condenses onto the surfaces? Where does it come from if it hadn't previously condensed on that surface?

    Water doesn't have to condense to get on a surface. The shower cubicle is wet because you spray water at it. The kettle is wet because you fill it with water. The clothes are wet because you wash them. Almost all materials have a film of water adsorbed to the surface all the time - and that usually does arise from condensation. Many materials are hygroscopic - they also have water absorbed within them - soft furnishings are a good example.

    If you reduce the humidity, some of it evaporates and that takes energy. Yes there's no specific heating provided. The evaporation causes the temperature of the surface to drop by a small amount and that difference is then made up from the environment and then by the heating system. I say again, the energy has to come from somewhere.

    Unless you're talking about an extremely vapour impermeable building, much of the vapour that condenses will also migrate through the wall / ceiling anyway, not just continuously condense and evaporate within the building envelope.

    In most buildings, the layer of paint on the surface of walls and ceilings specifically makes them particularly impermeable. Even in a breathable building, most of the movement of moisture is mass transport carried along with the air, not via the fabric of the building.

    There obviously is a net energy of vapourisation that has to come from somewhere, but this isn't new energy, it's energy that was already being spent in the form of showers, drying clothes etc.

    No, that's the whole point. If you evaporate extra water then there is extra energy expended to do so. Just because its a relatively small and diffuse amount of energy.

    I suggest reading some of Tim Padfield's stuff or the papers written by Passivhaus researchers.
    • CommentAuthorqeipl
    • CommentTimeSep 29th 2012
     
    Posted By: davidfreeboroughDo your COP figures for the Ecocent include energy recovered from latent heat? If so, what relative humidity was assumed for these?

    Yes. 50%RH.

    There is no cumulative energy gain from the exhaust heat pump

    The outside temperature here today is 9C.
    The weather is overcast and windy with occasional squalls of heavy rain.
    There is considerable windchill and no solar gain.

    An unoccupied bedroom in my house is at 18C.
    The only heat source in the bedroom is UFH which runs off the Ecocent cylinder (no bodies, no lights, no electric equipment).
    The Ecocent is set to run when the inlet water temp falls below 42C.
    The Ecocent has run once this morning for a period of around 45 minutes.
    The air supply to the Ecocent comes from outside and passes through the bedroom.
    The water in the cylinder is now back up to temp (47C).

    The bedroom has been losing energy to outside via fabric losses.
    The bedroom has had c.110m^3 of cold air drawn into it by the heat pump.
    The temp in the bedroom is now 18C, and has been throughout the morning.
    How do you explain this?
    • CommentAuthorGavin_A
    • CommentTimeSep 30th 2012 edited
     
    Posted By: djh
    No, that's the whole point. If you evaporate extra water then there is extra energy expended to do so. Just because its a relatively small and diffuse amount of energy.

    Not to any great extent.

    in the case of extra steam from showers, this is merely energy in the form of heat that would have been lost down the drain if it wasn't used to create more steam due to the lower RH. Likewise, the water on the shower screen etc would evaporate eventually anyway unless the RH was 100%, it's only the time it takes to evaporate that would change.

    A quick bit of research gleans the following vapour sources that are entirely or almost entirely independent of the RH levels, and need no additional energy to evaporate than they would do at higher RH levels.

    1kg a day of water vapour per person from respiration and sweating
    0.5-1kg a day per person from showers
    0.25kg a day dishwashing
    0.24kg a day / meal from cooking
    3kg a load of washing (assuming its' dried inside, and would have been dried inside regardless)

    in a 4 person house with indoor clothes drying, that's probably around 9kg a day of water vapour that's independent of RH levels entirely, or around 5.6kWh a day of latent heat available for recovery.

    Granted 5.6kWh a day isn't a vast amount, and this is really why this tech should only be used in extremely well insulated and air tight buildings, and's why the energy consumption levels rocket if people start going much above these sort of levels of energy demand, as at that point all the other arguments raised in this thread start to become valid. I suspect that UK builders simply aren't getting anything close to these sorts of levels of additional heat requirements in their buildings (on top of body heat, heat from electrical appliances, passive solar gain etc).

    I agree that there will be a minor increase in energy used for vapourisation of a few small contributors to RH levels, but doubt this is more than 10-15% of the value in most well sealed buildings. The rest is energy that would be expended regardless, and the choice is to recover that energy, or lose it to the outside air.

    You're right to an extent about the vapour permiability of the walls, as I'dforgotten we're dealing with highly insulated, air tight houses which will presumably have vapour barriers in walls, ceiling etc. In these cases the vapour would have left via the ventilation, as previously discussed, and this is how the RH equilibrium would be maintained. In older houses a significant proportion of vapour does migrate through the walls, and particularly the ceiling, though most would still leave via drafts etc.

    http://www.ornl.gov/sci/buildings/2010/Session%20PDFs/71_New.pdf
    • CommentAuthorGavin_A
    • CommentTimeSep 30th 2012
     
    btw - I've just scanned some of Tim Padfields work, and it all seems to be to do with humidity buffering, which in no way conflicts with anything I've said.

    A meterial that acts as a humidity buffer absorbs and releases vapour acording to the RH of the air, but overall this process is energy neutral.
    • CommentAuthorGavin_A
    • CommentTimeSep 30th 2012
     
    just to add, from the above it seems that the energy available is quite well matched to water heating requirements, with minimal left over for space heating.

    I'd also think that whether people use gas for cooking, and if they do dry their clothes inside, or use a tumble drier / dry them outside, will make a significant difference to the latent heat energy available. Gas cooking would probably account for another 0.5kg or so of water vapour a day on average.
    • CommentAuthorGavin_A
    • CommentTimeSep 30th 2012
     
    Also, these heat figures relate only to those needed to replace heat lost through the fabric of the building and any air changes other than those through the EAHP system.

    That still seems to be a pretty extreme target to reach for daily heating requirements, possibly suited to something approaching Tony's level of insulation and air tightness if it's the sole actual heating source.

    I think I'd only contemplate it in a situation with something like a wood burning stove or similar to add heat in the peak of winter, and use the EAHP for background heating the rest of the year, but only in an extremely well insulated and air tight situation. Or possibly just to provide water heating after a MHRV unit to stop an ASHP being needed to heat water at the worse COP levels that'd involve.
    • CommentAuthorGavin_A
    • CommentTimeSep 30th 2012
     
    I just realised I've made a bit of an error last night, and the 5.6kWh figure I came up with only relates to the actual latent heat figure, not for the actual energy contained in the heating / cooling of that mass of water vapour on top of the latent heat figures.

    I think I'm right that this only actually makes about 0.1kWh a day difference though, but I'm a bit rusty at these calcs.

    This ain't a lot of heat per day, if I'm right that this is basically the only actual source of additional heat available on top of the electricity used directly in the compressor, pump etc.

    It'd basically mean that anything over these levels would need to be supplied by other means, and in the case of a house that's 100% heated by these units those other means would be an immersion type heater. The first approximately 7-8 kwh then would be at a very good COP, but anything over that is suddenly at a COP of 1.
  3.  
    Posted By: qeiplHow do you explain this?
    The Ecocent will only cool the house when it is actually running. If it runs for 45 minutes then the Ventilation Heat Loss attributable to the exhaust heat pump will be 1936 W x 0.75 hours = 1.45kWh & the Net Heat Gain will be 745 x 0.75 = 0.56 kWh. The energy required to heat the water from 42°C to 47°C is 1.74 kWh.

    This leaves 1.18 kWh unaccounted for. This is not a huge amount of energy & could easily be provided by thermal mass in a well insulated house, particualrly as it has been quite warm until recently. Yesterday afternoon I left the windows open for a couple of hours without an appreciable change in inside air temperature.

    I have already said that you clearly have a system that works for you. My argument is that this does not prove that exhaust heat pumps should be routinely specified for residential properties, especially those owned by housing associations. If they are specified then an alternative form of heat is needed mid-winter, e.g. external ASHP or gas boiler. I note that you use solid fuel for this purpose.

    David
    • CommentAuthorGavin_A
    • CommentTimeOct 1st 2012
     
    'My argument is that this does not prove that exhaust heat pumps should be routinely specified for residential properties, especially those owned by housing associations. If they are specified then an alternative form of heat is needed mid-winter, e.g. external ASHP or gas boiler. '

    I'd have to agree with this.

    Possibly in a really really well built eco house or something, but I just don't believe standard UK builders are capable at the moment of achieving those levels of air tightness and insulation, no matter what the design specs say, unfortunately.
    • CommentAuthorqeipl
    • CommentTimeOct 2nd 2012
     
    Gavin,

    My understanding of RH and enthalpy is as follows:

    RH: the proportion of the available energy in the air that has been used for evaporation.

    Enthalpy: the total energy content of air (sensible + latent).

    If air is at 50%RH does this mean that half of the energy in it is sensible and half latent?

    I've tried to find the answer to this online, but failed.

    Malcolm
    • CommentAuthorEd Davies
    • CommentTimeOct 2nd 2012 edited
     
    Posted By: qeiplIf air is at 50%RH does this mean that half of the energy in it is sensible and half latent?

    No. It means that the partial pressure of water vapour in the air is half what it would be if the air was in equilibrium with a flat surface of pure water at the same temperature. Here equilibrium means that the rate of evaporation from the surface is equal to the rate of condensation onto it.

    In other words, 100% RH corresponds to the equilibrium vapour pressure.

    http://en.wikipedia.org/wiki/Relative_humidity

    That's also often called the saturation vapour pressure (e.g., in that Wikipedia article). However, that's a very misleading name as it conjures the 18th century notion that the air can “hold” a certain amount of water vapour and condensation happens when that amount is exceeded. That idea breaks down and becomes confusing as soon as the water is not pure or the surface is not flat (e.g., droplets in a cloud or capillaries in materials like wood).

    The equilibrium vapour pressure rises very rapidly with temperature. A good rule of thumb to start with is that it doubles for every 10 °C rise. For more accuracy browse from:

    http://en.wikipedia.org/wiki/Arden_Buck_equation

    To a pretty good approximation the mass of water vapour is proportional to the partial pressure (if the temperature is kept constant) so the RH is also the proportion by mass (to the “equilibrium vapour density”).
    • CommentAuthorqeipl
    • CommentTimeOct 2nd 2012
     
    Thanks Ed.
    • CommentAuthorEd Davies
    • CommentTimeOct 2nd 2012
     
    Looking at it another way:

    Posted By: qeiplRH: the proportion of the available energy in the air that has been used for evaporation.


    No, RH has nothing directly to do with energy.

    To see this consider an airtight and strong room at 20 °C and 50% RH with the moist air at typical room pressures (say 100 kPa). Suppose you use some sort of molecular sieve to remove all the dry air (nitrogen, oxygen, argon, CO₂, etc) but leave the water vapour behind.

    The equilibrium vapour pressure of water vapour does not change much with changes of total pressure (of the order of 1% or so in a case like this) so the relative humidity stays pretty much the same. We still have the same amount of water vapour as before so the latent heat also stays the same.

    However, all the sensible heat stored in the dry air has gone through the sieve with it so substantially the same RH but totally different ratio of latent to sensible heat.
    •  
      CommentAuthorSteamyTea
    • CommentTimeOct 2nd 2012
     
    Ed

    A great explanation.
    Karl Popper would be proud of you.
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